Question

Calculate the volume in milliliters of a 3.5 mp;/L silver perchlorate solution that contains 75.0 g of silver perchlorate . Round your answer to significant digits.

Answer 1

To find the volume in milliliters of a 3.5 M silver perchlorate solution containing 75.0 g of silver perchlorate, first calculate the moles of solute, then use the molarity to find the volume in liters, and finally convert the volume to milliliters, resulting in 149.5 mL.

Step-by-step explanation:

To calculate the volume in milliliters of a 3.5 M silver perchlorate solution that contains 75.0 g of silver perchlorate, we can use the following steps:

1. First, determine the molar mass of silver perchlorate (AgClO4). Using the periodic table, the molar mass is calculated as the sum of the mass of silver (Ag), chlorine (Cl), and four oxygen (O) atoms. The molar mass of AgClO4 would be 143.32 g/mol (107.87 + 35.45 + 4(16)).
2. Convert the amount of silver perchlorate from grams to moles using its molar mass: 75.0 g / 143.32 g/mol = 0.5234 mol.
3. Use the concentration of the solution to find the volume in liters: 0.5234 mol / 3.5 mol/L = 0.1495 L.
4. Convert the volume from liters to milliliters: 0.1495 L x 1000 mL/L = 149.5 mL.

This volume calculation should be reported to three significant figures because the molar mass and given mass are measured to that precision.