For this case we have that by definition, the equation of the line in the slope-intersection form is given by:
![y=mx+b](https://img.qammunity.org/2021/formulas/mathematics/middle-school/yj5waqmoy4i54laybzhhshd88hyo5w5rj5.png)
Where:
m: It is the slope of the line
b: It is the cut-off point with the y axis
We have the following points through which the line passes:
![(x_ {1}, y_ {1}) :( 6,13)\\(x_ {2}, y_ {2}): (7900,5)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/7flcwizzcijh0vclc9siap7k4leypedfad.png)
We find the slope of the line:
![m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {5-13} {7900-6} = \frac {-8} {7894} = - \frac {4} {3947}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/y3n1mfca2tpygmt0kg62q509kf3ns11yna.png)
Thus, the equation of the line is of the form:
![y = - \frac {4} {3947} x + b](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wmx7zdraqvyso6w3oyku5rwmgf26uhft1u.png)
We substitute one of the points and find b:
![13 = - \frac {4} {3947} (6) + b\\13 = - \frac {24} {3947} + b\\13+ \frac {24} {3947} = b\\b = \frac {51335} {3947}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/up74r12uf46nwyutvhzpk9vitw8ocswedl.png)
Finally, the equation is:
![y = - \frac {4} {3947} x + \frac {51335} {3947}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6svufu22913957tykmiuhh8scrpl67djno.png)
Answer:
![y = - \frac {4} {3947} x + \frac {51335} {3947}](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6svufu22913957tykmiuhh8scrpl67djno.png)