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Equation for ( 6, 13) ( 7900, 5 )

User Arjoonn
by
6.3k points

1 Answer

4 votes

For this case we have that by definition, the equation of the line in the slope-intersection form is given by:


y=mx+b

Where:

m: It is the slope of the line

b: It is the cut-off point with the y axis

We have the following points through which the line passes:


(x_ {1}, y_ {1}) :( 6,13)\\(x_ {2}, y_ {2}): (7900,5)

We find the slope of the line:


m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {5-13} {7900-6} = \frac {-8} {7894} = - \frac {4} {3947}

Thus, the equation of the line is of the form:


y = - \frac {4} {3947} x + b

We substitute one of the points and find b:


13 = - \frac {4} {3947} (6) + b\\13 = - \frac {24} {3947} + b\\13+ \frac {24} {3947} = b\\b = \frac {51335} {3947}

Finally, the equation is:


y = - \frac {4} {3947} x + \frac {51335} {3947}

Answer:


y = - \frac {4} {3947} x + \frac {51335} {3947}

User Mazen Ezzeddine
by
6.2k points
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