Question

The sum of four consecutive even integers is 212. Find the integers.

Answer 1

50 , 52 , 54 , 56

Explanation:

Let (x-3), (x-1),(x+1) & (x+3) are four consecutive numbers whose sum is 212 then

x-3+x-1+x+1+x+3=212

4x=212

x=(212/4)

x=53

So numbers are 50,52,54 & 56

Answer 2

• The required integers are 50, 52, 54 and 56

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Explanation:

Let the four consecutive even integers be:

• First integer = x
• Second integer = x + 2
• Third integer = x + 4
• Fourth integer = x + 6

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`{ \underline{ \pmb{According \: to \: the \: question:}}}`

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• Sums of four integers = 212

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`\: \: \: \: \dashrightarrow \: \: \: \sf x + x + 2 + x + 4 + x + 6 = 212 \\`

`\: \: \: \: \dashrightarrow \: \: \: \sf 4x + 12 = 212 \\`

`\: \: \: \: \dashrightarrow \: \: \: \sf 4x = 212 - 12 \\`

`\: \: \: \: \dashrightarrow \: \: \: \sf 4x = 200 \\`

`\: \: \: \: \dashrightarrow \: \: \: \sf x = (200)/(4) \\`

`\: \: \: \: { \pmb{ \sf{ \pink{\dashrightarrow \: \: \: \sf x = 50}}} } \\`

Hence,

• First integer = x = 50
• Second integer = x + 2 = 52
• Third integer = x + 4 = 54
• Fourth integer = x + 6 = 56

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`{ \underline {\therefore{ \pmb{ \frak{ The \: required \: integers \: are \: 50, 52,54 \: and \: 56.}}}}} \\`