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The reaction between 2-methyl-2-pentanol and HBr to yield 2-methyl-2-pentene is probably:

User Tim Kryger
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Answer: it is an SN1 mechanism.

Step-by-step explanation:

The reaction between 2-methyl-2-pentanol and HBr to yield 2-methyl-2-pentene is an SN1 mechanism.

WHAT IS AN SN1 REACTION: SN1 is a substitution reaction in which the reaction centre gives racemization of stereochemistry. Also, SN1 reaction are unimolecular.

In SN1, the rate determining step depends on the decomposition of a single molecular species. At the intermediate, there is carbocation in this reaction.

SN1 REACTION MECHANISM: The following are the steps involving the mechanism for SN1 reaction of 2-methyl-2-pentanol with HBr.

Step 1:

ACID-BASE REACTION: here, we have the protonation of the oxygen in the alcohol. The protonation makes it a good leaving group.

Step 2:

C-O CLEAVAGE: the C-O bond breaks. This bond breaking is endothermic and this step is the rate determining step.

Step 3:

ATTACK ON THE BROMIDE ION.

The equation of reaction is given below:

C6H15O + HBr ------------> [intermediate] --------------> C6H12 (2-methyl-2-pentene).

The reaction between 2-methyl-2-pentanol and HBr to yield 2-methyl-2-pentene is probably-example-1
User Aldorado
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