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a 1507kg truck enters a corner with a radius of 465m with a centripetal force magnitude of 3410n. What is the truck’s speed?
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a 1507kg truck enters a corner with a radius of 465m with a centripetal force magnitude of 3410n. What is the truck’s speed?

User Kalle Gustafsson
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1 Answer

7 votes
7 votes

Answer:32.44m/s

Step-by-step explanation:

Centripetal force=(mass(velocity)^2)/r

3410=(1507v^2)/465

Cross product

3410×465=1507v^2

1585650=1507v^2

V^2=1585650/1507

V^2=1052.189781

V=√(1052.189781)

V=32.44joules

User ReturnVoid
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