Question

a jet plane traveling 1890 km/h pulls out of a dive by moving in an arc of radius 5.20km. what is planes acceleration in g's

Answer 1

`53 m/s^2`

Step-by-step explanation:

Unit conversions:

1890 km/h = 1890 km/h * 1000m/km * 1/3600 h/s = 525 m/s

5.2 km = 5200 m

Assume that the jets is traveling in perfect circular motion, we can calculate the centripetal acceleration of the motion:

`a = (v^2)/(r)`

where v = 525m/s is the velocity of the jet and r = 5200 is the radius of the arc

`a = (525^2)/(5200) = 53m/s^2`