Question

How many molecules are there in 8.00 grams of glucose, C6H12O6

Answer 1

To calculate the number of glucose molecules in 8.00 grams of glucose, first calculate the moles of glucose using its molecular weight (180.16 g/mol) and then multiply by Avogadro's number (6.022 × 10²³ molecules/mol), which results in approximately 2.67 × 10²² molecules.

Step-by-step explanation:

To determine the number of molecules in 8.00 grams of glucose (C₆H₁₂O₆), we first need to calculate the number of moles of glucose. The molecular weight of glucose is 180.16 g/mol, which is obtained by summing the atomic masses of each constituent atom (6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms).

Using the molecular weight, we calculate the moles of glucose:

• Number of moles = mass (in grams) / molar mass (in g/mol)
• Number of moles = 8.00 g / 180.16 g/mol
• Number of moles = 0.0444 mol (rounded to four decimal places)

Now, we use Avogadro's number, which is 6.022 × 10²³ molecules/mol, to find the number of glucose molecules:

• Number of molecules = number of moles × Avogadro's number
• Number of molecules = 0.0444 mol × 6.022 × 10²³ molecules/mol
• Number of molecules = 2.67 × 10²² molecules (rounded to two significant figures)

Therefore, there are approximately 2.67 × 10²² molecules of glucose in 8.00 grams of glucose.

Answer 2

molecules C6H12O6 = 2.674 E22 molecules.

Step-by-step explanation:

from periodic table:

⇒ molecular mass C6H12O6 = ((6)(12.011)) + ((12)(1.008)) + ((6)(15.999))

⇒ Mw C6H12O6 = 180.156 g/mol

⇒ mol C6H12O6 = (8.00 g)(mol/180.156 g) = 0.0444 mol C6H12O6

∴ mol ≡ 6.022 E23 molecules

⇒ molecules C6H12O6 = (0.0444 mol)(6.022 E23 molecules/mol)

⇒ molecules C6H12O6 = 2.674 E22 molecules