Question

Joey has budgeted $125 for his family of four to go to the fair.

Admission is $8 per person and each ride costs $1.25.
Food for the family costs $27.
They each ride the same number of rides.

What is the maximum number of rides each person in the family can ride and not go over Joey’s budget?

Answer 1

52 rides

Explanation:

125 - 8 - 8 - 8 - 8 = 93

93 - 27 = 66

66 ÷ 1.25 = 52.8

Since 52.8 rides we have to use only the whole numbers, so in this case 52.

Hope this helps!