212k views
0 votes
Y -2 = -(1/3) (x+6)
What is this written in standard form using integers

User Tokimon
by
8.1k points

1 Answer

6 votes

The standard form using integers is x + 3y = 0

Solution:

Given that we have to write the given equation in standard form

The standard form of an equation is Ax + By = C

In this kind of equation, x and y are variables and A, B, and C are integers

Let us convert the given equation to standard form

Given equation is:


\rightarrow y - 2 = -(1)/(3)(x + 6)

Multiply the terms inside bracket with constant outside the bracket in right hand side of equation


\rightarrow y - 2 =( (-1)/(3) * x )+ ((-1)/(3) * 6)\\\\\rightarrow y - 2 = (-x)/(3)-2

Simplify the right hand side of equation


\rightarrow y - 2 = (-x-6)/(3)

Move the 3 from R.H.S to L.H.S


\rightarrow 3(y-2) = -x-6\\\\\rightarrow 3y - 6 = -x - 6

Move the terms from R.H.S to L.H.S


\rightarrow x + 3y - 6 + 6 = 0\\\\\rightarrow x + 3y = 0

Thus the standard form is found

User JeffRamos
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories