Question

Y -2 = -(1/3) (x+6)
What is this written in standard form using integers

Answer 1

The standard form using integers is x + 3y = 0

Solution:

Given that we have to write the given equation in standard form

The standard form of an equation is Ax + By = C

In this kind of equation, x and y are variables and A, B, and C are integers

Let us convert the given equation to standard form

Given equation is:

`\rightarrow y - 2 = -(1)/(3)(x + 6)`

Multiply the terms inside bracket with constant outside the bracket in right hand side of equation

`\rightarrow y - 2 =( (-1)/(3) * x )+ ((-1)/(3) * 6)\\\\\rightarrow y - 2 = (-x)/(3)-2`

Simplify the right hand side of equation

`\rightarrow y - 2 = (-x-6)/(3)`

Move the 3 from R.H.S to L.H.S

`\rightarrow 3(y-2) = -x-6\\\\\rightarrow 3y - 6 = -x - 6`

Move the terms from R.H.S to L.H.S

`\rightarrow x + 3y - 6 + 6 = 0\\\\\rightarrow x + 3y = 0`

Thus the standard form is found