Question

An object undergoing simple harmonic motion takes 0.23 s to travel from one point of zero velocity to the next such point. The distance between those points is 32 cm. (a) Calculate the period of the motion.

Answer 1

Period of motion is 0.46 sec

Step-by-step explanation:

Object is undergoing SHM means object is moving from left to right and then right to left in a specific time called time period. As given object moves from left to right is 0.23 sec which is time for half cycle. Time period for one complete cycle is then

T=2t

T=2(0.23)

T=0.46 sec

Frequency of oscillation would be then

`f=(1)/(T)\\\\f=(1)/(0.46)\\\\\\f=2.17Hz`

Maximum amplitude of oscillation is the mid point of between left and rght end point:

`A=(d)/(2)\\\\A=(32)/(2)\\\\A=16\,cm`