201k views
4 votes
Water flows from a large drainage pipe at a rate of 950 gal/min. What is this volume rate of flow in (a) m3/s , (b) liters/min, and (c) ft3/s ?

User Gilad Naor
by
3.8k points

1 Answer

5 votes

Answer:


0.05997\ m^3/s


3596.1395\ L/min


2.11647\ ft^3/s

Step-by-step explanation:


1\ gal/min=(1)/(264* 60)\\\Rightarrow 950\ gal/min=950* (1)/(264* 60)\\\Rightarrow 950\ gal/min=0.05997\ m^3/s

Volume rate of flow is
0.05997\ m^3/s


1\ gal/min=3.78541\ L/min\\\Rightarrow 950\ gal/min=950* 3.78541=3596.1395\ L/min

Volume rate of flow is
3596.1395\ L/min


1\ gal/min=(1)/(7.481* 60)\\\Rightarrow 950\ gal/min=950* (1)/(7.481* 60)\\\Rightarrow 950\ gal/min=2.11647\ ft^3/s

Volume rate of flow is
2.11647\ ft^3/s

User David Heggie
by
4.1k points