Question 1

Water flows from a large drainage pipe at a rate of 950 gal/min. What is this volume rate of flow in (a) m3/s , (b) liters/min, and (c) ft3/s ?

Question 2

Answer:

$0.05997\ m^3/s$

$3596.1395\ L/min$

$2.11647\ ft^3/s$

Step-by-step explanation:

$1\ gal/min=(1)/(264* 60)\\\Rightarrow 950\ gal/min=950* (1)/(264* 60)\\\Rightarrow 950\ gal/min=0.05997\ m^3/s$

Volume rate of flow is
$0.05997\ m^3/s$

$1\ gal/min=3.78541\ L/min\\\Rightarrow 950\ gal/min=950* 3.78541=3596.1395\ L/min$

Volume rate of flow is
$3596.1395\ L/min$

$1\ gal/min=(1)/(7.481* 60)\\\Rightarrow 950\ gal/min=950* (1)/(7.481* 60)\\\Rightarrow 950\ gal/min=2.11647\ ft^3/s$

Volume rate of flow is
$2.11647\ ft^3/s$

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