Question

Oscilloscope amplitude and frequency problem. Study the above graph. The volts/div dial is set to 2 volts/div and the time/div dial is set to 5 msec/div. What is the peak-to-peak amplitude of the displayed signal? What is the frequency in khz?

Answer 1

To calculate the peak-to-peak amplitude, multiply the number of vertical divisions spanned by the waveform by the volts/division setting (30 volts in this case). For frequency in kHz, determine the period by the number of horizontal divisions for one cycle times the time/div setting, then take the reciprocal and convert to kHz (0.05 kHz here).

Step-by-step explanation:

To determine the peak-to-peak amplitude and frequency of a signal displayed on an oscilloscope, one must understand how to read the graph in accordance with the settings of the device. The given problem states that the oscilloscope's volts/division setting is 2 volts/div, and the time/division is set to 5 milliseconds/div. The peak-to-peak amplitude is the total vertical distance that the waveform spans on the display, measured in divisions and multiplied by the volts/division setting. The frequency is found by measuring the period of the waveform (the time it takes for one complete cycle of the waveform to occur) and then calculating the reciprocal of the period to get the frequency.

Let's assume from the description that the waveform spans 15 divisions peak-to-peak. To calculate the amplitude:

• Peak-to-peak amplitude = number of divisions × volts/division
• Peak-to-peak amplitude = 15 divisions × 2 volts/division
• Peak-to-peak amplitude = 30 volts

To calculate the frequency, let's assume the waveform takes up 4 divisions for one complete cycle:

• Period (T) = number of divisions × time/division
• Period (T) = 4 divisions × 5 milliseconds/division
• Period (T) = 20 milliseconds
• Frequency (f) = 1/T
• Frequency (f) = 1/(20 × 10-3 seconds)
• Frequency (f) = 50 Hz
• Frequency in kHz = Frequency (f) × 10-3
• Frequency in kHz = 50 × 10-3 kHz
• Frequency in kHz = 0.05 kHz

Answer 2

Amplitude = 8 Volts

Frequency = 0.067 kHz

Step-by-step explanation:

Note: The missing picture in question is attached for your review.

Given:

Volts/Div = 2 V/div

Time/Div = 5 msec/div

Finding Amplitude:

Now, as you can see in the attached picture, there are 4 division between two peaks of the waveform, so,

`Amplitude = 4 div/volts * 2 volts/ div )\\Amplitude = 8 Volts`

(Multiplying by 2 V/div because oscilloscope dial is set at 2 V/div)

Finding Frequency:

As can be seen in attached picture, 3 division are there for one complete cycle of waveform,so,

`Time Period = 3 div * 5msec /div\\Time Perod = 15 msec`

Since,

`Frequency = (1)/(Time Period)\\Frequency = (1)/(15m)\\Frequency = 0.067 kHz`