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5 votes
1.)
A.) tan 50°
B.) cot 50°
C.) sin 50°
D.) cos 50°
E.) cot 50°

1.) A.) tan 50° B.) cot 50° C.) sin 50° D.) cos 50° E.) cot 50°-example-1
User Onepan
by
8.5k points

2 Answers

1 vote

Answer:

cot 50 is thr answer

Explanation:

User Justqb
by
8.3k points
6 votes

Answer:


\cot 50 \textdegree

Explanation:


\cos\theta=(Adjacent)/(Hypotenuse)\\ \\\sin\theta=(Opposite)/(hypotenuse)\\ \\\tan\theta=(Opposite)/(Adjacent)\\ \\\cot\theta=(Adjacent)/(Opposite)\\ \\(\cos\theta)/(\sin\theta)=(\left((Adjacent)/(Hypotenuse)\right))/(\left((Opposite)/(Hypotenuse)\right))=(Adjacent)/(Opposite)=\cot\theta\\ \\\Rightarrow (\cos\theta)/(\sin\theta)=\cot\theta\\ \\Substitute \ \theta=50\textdegree\\ \\(\cos50\textdegree)/(\sin50\textdegree)=\cot50\textdegree

1.) A.) tan 50° B.) cot 50° C.) sin 50° D.) cos 50° E.) cot 50°-example-1
User Ardiana
by
7.7k points

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