Question

Which of the following represents the ground state electron configuration for the Mn3 ion?

Answer 1

`1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^2`

Step-by-step explanation:

The
`Mn^(+3)` has 22 electrons arround the nucleous. Its ground state configuration following the diagonal rule is:

`1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^2`

In term of the previous noble gas:

`[Ar] 4s^2 3d^2`