Question

Which is the simplified form of the expression (StartFraction (2 Superscript negative 3 Baseline) (x Superscript negative 3 Baseline) (y squared) Over (4 Superscript negative 2 Baseline) (x Superscript 4 Baseline) (y Superscript 6 Baseline) EndFraction) Squared

Answer 1

THE ANSWER IS C

Explanation:

on edge. :)

Answer 2

Answer:
`(4x^(14))/(y^(8))`

Explanation:

We have tthe following expression:

`((2^(-3) )/(x^(-3)) (y^(2))/(4^(-2)) (x^(4))/(y^(6)))^(2)`

Firstly, we have to solve the oeprations inside the parenthesis. Let's begin by grouping similar coefficients:

`((2^(-3) )/(4^(-2)) (x^(4))/(x^(-3)) (y^(2))/(y^(6)))^(2)`

Rewriting the expression:

`((4^(2) )/(2^(3)) x^(4) x^(3)(1)/(y^(4)))^(2)`

`((2x^(7) )/(y^(4)))^(2)`

Multiplying the exponent outside the parenthesis with the exponents inside:

`(4x^(14))/(y^(8))` This is the final result