Answer:
Explanation:
Lots of factoring here. Let's rewrite everything in its simplest, factored form:
![(((x-1)(x+3))/((x-4)) )/(((2x-1)(x+3))/((x+4)(x-4)) )](https://img.qammunity.org/2021/formulas/mathematics/high-school/m6rwq2ndi2g0ll7c1zqa7hs39cjdz73zj0.png)
The term (x - 4) cancels out completely, leaving us with
![((x-1)(x+3))/(((2x-1)(x+3))/((x+4)) )](https://img.qammunity.org/2021/formulas/mathematics/high-school/9n06boku1hzapiu7oji11cy9avvdsqag7k.png)
Let's get rid of that (x + 4) by multiplying both top and bottom by (x + 4) to get
![((x-1)(x+3)(x+4))/((2x-1)(x+3))](https://img.qammunity.org/2021/formulas/mathematics/high-school/dtef0bik6r52aknwr8ha6al6xrh7xwn8bx.png)
It's obvious now that the (x + 3) term cancels out, leaving us with
![((x-1)(x+4))/((2x-1))](https://img.qammunity.org/2021/formulas/mathematics/high-school/wxntzgbvsubzd514sqjau5y1thynk1f8k5.png)
Now all that's left to do is to FOIL out the numerator:
![(x^2+3x-4)/(2x-1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/r3pgbm8xb0fqeg37uipybyf16tl88xehfb.png)
The first choice is the one you want