Question

Passes through (4' -4) and (8, -10) how do you do it?​

Answer 1

`y = - (3)/(2)x + 2`

Explanation:

We want to find the equation of the line that passes through:(4 -4) and (8, -10)

We first find the slope using

`m = (y_2-y_1)/(x_2-x_1)`

We plug in

`x_1=4,x_2=-4,y_1=8,y_2=-10`

to get:

`m = ( - 10 - - 4)/(8 - 4) = ( - 6)/(4) = - (3)/(2)`

We now use the point-slope formula:

`y-y_1=m(x-x_1)`

This implies that:

`y - - 4 = - (3)/(2) (x - 4)`

`y = - (3)/(2) x + 6 - 4`

`y = - (3)/(2)x + 2`