Question

Please help me with four and five

Answer 1

4.
`(x + y)(x + 5y)`

5.
`\left(2m+3\right)\left(m-4\right)`

Explanation:

4.

First break it into groups:

`\left(x^2+xy\right)+\left(5xy+5y^2\right)`

Then factor out x from the first parentheses and 5y from the second one:

`x(x+y)`
`+`
`5y\left(x+y\right)`

Next, factor out x + y from the equation. This gives you:

`\left(x+y\right)\left(x+5y\right)`

5.

Break it into groups like the last one:

`\left(2m^2+3m\right)+\left(-8m-12\right)`

Then, factor out m from the first parentheses and -4 from the second parentheses:

`m\left(2m+3\right)-4\left(2m+3\right)`

Lastly, factor out 2m + 3 from the equation:

`\left(2m+3\right)\left(m-4\right)`