Question

Question > calculate the percent composition of each element in the following compounds

Th(SO4)2

Ca3(PO4)2

C6H12O6

PLEASE HELP HURRY

Answer 1

The percent composition of each element are :

1. Th(SO4)2 :

Th = 54.704% , S = 15.119% , O = 30.1759 %

2.Ca3(PO4)2

Ca = 38.76% , P = 19.97% , O = 41.265%

3.C6H12O6

C = 40.0% , H = 6.72% , O = 53.29%

Step-by-step explanation:

Formula calculate the percent composition

`% composition =(mass\ of\ given\ element)/(Molar\ mass)`

Molar mass of Th(SO4)2 = Mass of Th + 2(mass of S) + 8(mass of O)

= 232.03 + 2(32.06) + 8(16)

=232.03 +64.12+128

= 424.16

`% Th=(mass\ of\ Th)/(424.16)`

`=(232.03)/(424.16)`

= 54.704%

`% S=(2(mass\ of\ S))/(424.16)`

`=(64.12)/(424.16)`

= 15.119%

`% O=(8(mass\ of\ O))/(424.16)`

`= (128)/(424.16)`

= 30.17%

2.Ca3(PO4)2

Molar mass of Ca3(PO4)2 = 3(Mass of Ca) + 2(mass of P) + 8(mass of O)

= 3(40) + 2(30 .9) + 8(16)

= 120 + 61.8 + 128

=310.176

`% Ca =(3(mass\ of\ Ca))/(310.176)`

`=(120)/(424.16)`

38.76%

`% P=(2(mass\ of\ P))/(310.176)`

`=(61.8)/(310.176)`

= 19.97%

`% O=(8(mass\ of\ O))/(310.176)`

`=(128)/(424.16)`

= 41.26 %

3.

C6H12O6

Molar mass of C6H12O6 = 6(Mass of C) + 12(mass of O) + 6(mass of O)

= 6(12) + 12(1) + 6(15.99)

=180

`% O=(6(mass\ of\ O))/(180)`

`=(95.94)/(180)`

= 53.28%

`% C=(6(mass\ of\ C))/(180)`

`% C=(72)/(180)`

= 40%

`% H=(12(mass\ of\ C))/(180)`

`=((12)/(180)`

= 6.713%