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Which expression is equivalent to RootIndex 3 StartRoot 32 x Superscript 8 Baseline y Superscript 10 Baseline EndRoot?

User Callam
by
3.3k points

2 Answers

4 votes

Answer:

C

Explanation:

The Answer is C on Edge.

User Skyde
by
4.0k points
1 vote

Answer:

The equivalent expression to the given expression is
\sqrt[3]{32x^8y^(10)}=2x^2y^3\sqrt[3]{4x^2y}

Explanation:

The given expression is
\sqrt[3]{32x^8y^(10)}

To find the equivalent expression:


\sqrt[3]{32x^8y^(10)}=(32x^8y^(10))^{(1)/(3)}

We may write the above expression as below:


=(32^{(1)/(3)})((x^8)^{(1)/(3)})((y^(10))^{(1)/(3)})


=(2)((4)^{(1)/(3)})(x^6)* (x^2)(x^{(2)/(3)})(y^3)(y^{(1)/(3)}) (using square root properties)


=(2\sqrt[3]{4})(x^2\sqrt[3]{x^2})(y^3\sqrt[3]{y}) (combining the like terms and doing multiplication )


=2x^2y^3\sqrt[3]{4x^2y}

Therefore
\sqrt[3]{32x^8y^(10)}=2x^2y^3\sqrt[3]{4x^2y}

Therefore the equivalent expression to the given expression is
\sqrt[3]{32x^8y^(10)}=2x^2y^3\sqrt[3]{4x^2y}

User Ross Peoples
by
3.4k points