Question

3. Suppose the mystery bag had resulted in the following number of red chips. Using the simulated sampling distributions found earlier in this lesson, find a margin of error in each case.

a. The number of red chips in a random sample of size 30 was 10.
b. The number of red chips in a random sample of size 30 was 21.
c. The number of red chips in a random sample of size 50 was 22.

Answer 1

b

Explanation:

Answer 2

a) 0.172

b) 0.167

c) 0.1404

Explanation:

Margin of error, E =
`2*\sqrt{(p(1-p))/(n)}`

here,

p = probability of the event

n = sample size

a) n = 30

p = 10 ÷ 30 = 0.333

Therefore,

E =
`2*\sqrt{(0.333(1-0.333))/(30)}`

= 2 × 0.0861

= 0.172

b) n = 30

p = 21 ÷ 30 = 0.7

Therefore,

E =
`2*\sqrt{(0.7(1-0.7))/(30)}`

= 2 × 0.0836

= 0.167

c) n = 30

p = 22 ÷ 50 = 0.44

Therefore,

E =
`2*\sqrt{(0.44(1-0.44))/(50)}`

= 2 × 0.0702

= 0.1404