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What is the solution to the exponential equation 1/64= 2^x+1

1 Answer

1 vote

Answer:

x = - 7

Explanation:

We have to get the solution to the exponential equation
(1)/(64) = 2^((x + 1)).

Now,
(1)/(64) = 2^((x + 1))


(1)/(2^(6)) = 2^((x + 1))


2^(- 6) = 2^((x + 1))

{Since we know the properties of exponent as
a^(- b) = (1)/(a^(b) ) }

⇒ - 6 = (x + 1)

{Since the base are same i.e. 2 so, we can equate the power terms of both sides}

x = - 6 - 1 = - 7 (Answer)

User Taner
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