Question

Calculate the number of moles of sodium oxide that should be produced with 6.50 g of sodium react with oxygen gas

Answer 1

As per the values, 0.561 moles of sodium oxide should be produced with 6.50 g of sodium reacting with oxygen gas.

Step-by-step explanation:

To calculate the number of moles of sodium oxide produced, we first need to write the balanced chemical equation for the reaction between sodium and oxygen. The equation is:

`4Na + O2 -- 2Na2O`

From the equation, we can see that 4 moles of sodium react with 1 mole of oxygen gas to produce 2 moles of sodium oxide. So, the mole ratio is: 4 moles Na : 1 mole O2 : 2 moles Na2O

To find the number of moles of sodium oxide produced, we use the given mass of sodium and its molar mass:

`6.50 g Na * (1 mol Na / 22.99 g Na) * (2 mol Na2O / 4 mol Na)`

= 0.561 mol Na2O

Therefore, 0.561 moles of sodium oxide should be produced with 6.50 g of sodium reacting with oxygen gas.

Answer 2

First of all write a balanced equation.
4Na + O2 -> 2Na2O
You are starting with a mass of sodium. You need to use sodium’s molar mass. Take this quantity times mole to mole ratio between sodium and sodium oxide to get moles of sodium oxide produced.
.141 moles of sodium oxide produced