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The heat of fusion of lead is 23.1 J/g. How much heat is absorbed as 85.0 g melt at
328°C?

User Eeyore
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1 Answer

5 votes

Answer:

Q = 1964 J

Step-by-step explanation:

Data Given:

latent heat of fusion for Lead (Lf)= 23.1 J/g

amount of ice (mass) = 85.0 gram

heat required to melt lead (Q) =?

Solution:

Latent heat of fusion: the amount of heat that required to melt certain amount of a substance. The total heat absorbed by substance is proportional to the total heat of fusion of the material.

Formula Used

Q = mLf

Q = heat required to melt a substance

m = mass of the substance

Lf =latent heat of fusion

put values in above formula

Q = mLf

Q = 85 g x 23.1 J/g

Q = 1964 J

User Bizmarck
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