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How do I solve this? It’s on Khan Academy

How do I solve this? It’s on Khan Academy-example-1
User Filcab
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1 Answer

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AC being parallel to RP makes the triangles ABC and RBP similar. This means corresponding sides occur in the same ratio, so that


(AC)/(RP)=(BC)/(BP)=(AB)/(RB)

It's not clear from the picture what it is that you're supposed to find, but from the above relation we have


(18)/(RP)=(BP+10)/(BP)=\frac{14+7}7

From this it follows that


(18)/(RP)=\frac{21}7=3\implies RP=\frac{18}3=6

and


(BP+10)/(BP)=\frac{21}7=3\implies BP+10=3BP\implies2BP=10\implies BP=5

User Abhshkdz
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