Question

You are moving the robot to your classroom, which measures 30 feet by 40 feet.

1. Draw the classroom set up on a coordinate plane using (30,40) as the northeast vertex.
2. The robot was initially placed at position (6,9), and at tt = 2 seconds, its position is (10,15). a. How far did the robot travel in 2 seconds.
b. What is the speed of the robot?

Answer 1

1) See figure attached

2)

a)
`d = √((x_2 -x_1)^2 +(y_2 -y_1)^2)`

And if we replace we got:

`d = √((10 -6)^2 +(15 -9)^2)= 7.211`

b)
`V = (d)/(t)`

And if we replace we got:

`V = (7.211 ft)/(2 sec)=3.606 s`

Explanation:

Part 1

We can see the plot in the figure attached.

Part 2

a)

For this case we have two points
`(x_1 , y_1) = (6,9) , (x_2 , y_2) = (10,15)`

And we want to find the distance travelled between these two points and we can use the following formula from the euclidian distance between two points:

`d = √((x_2 -x_1)^2 +(y_2 -y_1)^2)`

And if we replace we got:

`d = √((10 -6)^2 +(15 -9)^2)= 7.211`

b)

Since it takes two seconds in order to go from (6.9) to (10,15) we can use the definition of velocity:

`V = (d)/(t)`

And if we replace we got:

`V = (7.211 ft)/(2 sec)=3.606 s`