Question

A basketball has a diameter of 9.5

cm.

Which of the expressions shows how to determine the volume of air the basketball can hold?

A
34π(4.75)3

B
34π(9.5)3

C
43π(4.75)3

D
43π(

Answer 1

I also think it's 4/3 ( 4.75 ) 3

Answer 2

C.
`(4)/(3)\pi\cdot(4.75)^3\ cm^3`

Explanation:

The volume of the ball with radius R can be calculated using formula

`V=(4)/(3)\pi R^3`

A basketball has a diameter of 9.5 cm, so its radius is

`R=(D)/(2)=(9.5)/(2)=4.75\ cm`

Hence, the volume of air the basketball can hold is

`V=(4)/(3)\pi\cdot(4.75)^3\ cm^3`