Question

What is the graph to j

Answer 1

Substitute x = -9 and x = -3 into
`y=5-\frac13x`

`\implies y=5-\frac13(-9)=8`

`\implies y=5-\frac13(-3)=6`

Plot a closed circle at (-9, 8) and and open circle at (-3, 6).

Connect the points with a line segment.

Substitute x = -3 and x = 8 into
`y=\frac23x`

`\implies y=\frac23(-3)=-2`

`y=\frac23(8)=(16)/(3)`

Plot closed circles at (-3, 2) and (8, 16/3).

Connect the points with a line segment.