Question

Construct a ∆RBI in which ∠IRB=60° , BI=5.7 cm, ∠RBI = 90°
plssssssssss help me

Answer 1

The construction is shown below.

Explanation:

Given:

A triangle RBI with
`\angle IRB=60\°,\angle RBI=90\°,BI=5.7\ cm`

Since triangle RBI is a right angled triangle, the measure of angle RIB is given as:

∠RIB = 90° - 60° = 30°

Construction:

Step 1:

Draw a vertical line segment using a meter scale of length 5.7 cm. Label the top end point as 'I' and bottom point as 'B'.

Step 2:

Now, using a protractor construct an angle of 90° from point B with the line IB. Draw a line passing through the 90 degree mark and point 'B'.

Step 3:

Using the protractor, mark angle 30° from point 'I' with the line IB. Draw a line passing through the 30 degree mark till it intersects the line obtained in step 2.

Label the point of intersection of the lines from step 2 and step 3 as 'R'.

Thus, the resulting triangle obtained is ΔRBI.