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What is the area of a right triangle with the given vertices? A(3,1) , B(5,4) , C(6,−1)

User Theateist
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1 Answer

2 votes

Answer:


(13)/(2) square units

Explanation:

We are given that vertices of a right triangle are A(3,1) ,B(5,4) and C(6,-1).

We have to find the area of triangle.

We know that area of triangle=
(1)/(2)\mid (x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2))\mid


x_1=3,x_2=5,x_3=6


y_1=1,y_2=4,y_3=-1

Substitute the values in the formula then we get

Area of right triangle =
(1)/(2)\mid (3(4+1)+5(-1-1)+6(1-4))\mid

Area of right triangle =
(1)/(2)\mid (15-10-18)\mid

Area of right triangle =
(1)/(2)* 13=(13)/(2) square units

User Pankaj Suryawanshi
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