Answer:
square units
Explanation:
We are given that vertices of a right triangle are A(3,1) ,B(5,4) and C(6,-1).
We have to find the area of triangle.
We know that area of triangle=
![(1)/(2)\mid (x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2))\mid](https://img.qammunity.org/2021/formulas/mathematics/high-school/f4yr1q0cqbm3alnw3142doencjhpzowfid.png)
![x_1=3,x_2=5,x_3=6](https://img.qammunity.org/2021/formulas/mathematics/high-school/wr7x0r5k2cgimzoudz9q8cp8nmwf2e29lh.png)
![y_1=1,y_2=4,y_3=-1](https://img.qammunity.org/2021/formulas/mathematics/high-school/qkq89pxdgnxsi3ym1jjhz8ximuyizzec8v.png)
Substitute the values in the formula then we get
Area of right triangle =
![(1)/(2)\mid (3(4+1)+5(-1-1)+6(1-4))\mid](https://img.qammunity.org/2021/formulas/mathematics/high-school/sh479y4ct224j21b0karbnfvdxokxn0ii8.png)
Area of right triangle =
![(1)/(2)\mid (15-10-18)\mid](https://img.qammunity.org/2021/formulas/mathematics/high-school/igjeqrzpzw5dpl4so9hu0fjxrjysmhtp80.png)
Area of right triangle =
square units