Question

The temperature of the Sun’s atmosphere near the surface is about 6000 K, and the concentration of atoms is about 1015 particles/m3. What are the average pressure and density of its atmosphere? What assumptions did you make to solve the problem?

Answer 1

average pressure = 8.314 ×
`10^(-5)` pascal

density = 1.66 ×
`10^(-12)` kg/m³

Step-by-step explanation:

given data

temperature of sun = 6000 K

concentration of atoms =
`10^(15)` particles/m³

to find out

average pressure and density of its atmosphere

solution

first we get here average pressure of atmosphere that is express as

average pressure =
`(nRT)/(V)` .............1

put here value we get

average pressure =
`(10^15*8.314*6000)/(6*10^(23))`

average pressure = 8.314 ×
`10^(-5)` pascal

and

density of atmosphere will be

density =
`(nM)/(V)` .............2

density =
`(10^(15)*1.66*10^(-27))/(1)`

density = 1.66 ×
`10^(-12)` kg/m³