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1. what is x? (picture 1 and 2)

2. What is the length of NO? (3rd picture)
3. If LB = 6 and LN = 2x+5, what is x? (fourth picture)

1. what is x? (picture 1 and 2) 2. What is the length of NO? (3rd picture) 3. If LB-example-1
1. what is x? (picture 1 and 2) 2. What is the length of NO? (3rd picture) 3. If LB-example-1
1. what is x? (picture 1 and 2) 2. What is the length of NO? (3rd picture) 3. If LB-example-2
1. what is x? (picture 1 and 2) 2. What is the length of NO? (3rd picture) 3. If LB-example-3
1. what is x? (picture 1 and 2) 2. What is the length of NO? (3rd picture) 3. If LB-example-4
User Dove
by
8.8k points

1 Answer

5 votes

Answer:

Part 1)
x=6

Part 2)
x=5,75

Part 3)
NO=80\ units

Part 4)
x=3,5

Explanation:

Part 1) Find the value of x

we know that

In a parallelogram opposites sides are congruent and parallel

In this problem

GH=FE

substitute the given values


2x+10=22

solve for x

subtract 10 both sides


2x=22-10


2x=12

Divide by 2 both sides


x=6

Part 2) Find the value of x

we know that

In a parallelogram opposites sides are congruent and parallel

In this problem

FG=EH

substitute the given values


4x+5=28

solve for x

subtract 5 both sides


4x=28-5


4x=23

divide by 4 both sides


x=5,75

Part 3) What is the length of NO?

step 1

Find the value of x

we know that

In a parallelogram opposites sides are congruent and parallel

In this problem

NO=ML

substitute the given values


4x+20=2x+50

solve for x

Group terms


4x-2x=50-20


2x=30

Divide by 2 both sides


x=15

step 2

Find the value of NO

we have that


NO=4x+20

substitute the value of x


NO=4(15)+20=80\ units

Part 4) we know that

The diagonals in a parallelogram bisect each other

so

LB=BN

LN=LB+BN ----> by addition length postulate

LN=2LB

substitute the given values


2x+5=2(6)

solve for x


2x+5=12

subtract 5 both sides


2x=12-5


2x=7

Divide by 2 both sides


x=3,5

User Dmitry Samuylov
by
8.4k points

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