Question

Find three consecutive even integers such that the sum of the first, twice the second, three times the third is -76. What is the number?

(the three numbers is the same number)

Answer 1

The numbers are -14,-13 and -12

Explanation:

The correct question is

Find three consecutive integers such that the sum of the first, twice the second and three times the third is -76. What is the number?

Let

x ----> the first consecutive integer

x+1 ---> the second consecutive integer

x+2 ---> the third consecutive integer

we have that

`x+2(x+1)+3(x+2)=-76`

solve for x

apply distributive property

`x+2x+2+3x+6=-76`

Combine like terms

`6x+8=-76`

subtract 8 both sides

`6x=-76-8`

`6x=-84`

Divide by 6 both sides

`x=-14`

so

`x+1=-14+1=-13`

`x+2=-14+2=-12`

therefore

The numbers are -14,-13 and -12