Answer:
A. Between 14 and 15.
Explanation:
Let x be the one leg of the right triangle.
We have been given that the legs of a right triangle are in the ratio of 3 to 1. So, the other leg of the right triangle would be 3x.
We are also told that the length of the hypotenuse of the triangle is √40.
Using Pythagoras theorem, we can set am equation as:
![x^2+(3x)^2=(√(40))^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/b5di2fg9c420ftpli5s9ahdkmlaf2a5x9o.png)
Let us solve for x.
Take square root of both sides:
The other leg would be
.
The perimeter of the triangle would be:
![\text{Perimeter of triangle}=2+6+√(40)](https://img.qammunity.org/2021/formulas/mathematics/high-school/zrkwcxniat3399l343jgft0oc5qe8p4uh1.png)
![\text{Perimeter of triangle}=2+6+6.324555](https://img.qammunity.org/2021/formulas/mathematics/high-school/vffd8x9zetk6na60kopcu91xqr0seexlod.png)
![\text{Perimeter of triangle}=14.324555](https://img.qammunity.org/2021/formulas/mathematics/high-school/oz3weqifpyfj49ioogcfhvsngs8977qzdb.png)
Therefore, the perimeter of the triangle is between 14 and 15 and option A is the correct choice.