Answer:
![d < 20\ donuts](https://img.qammunity.org/2021/formulas/mathematics/middle-school/t8h5ysrjo3vmxs4h2fwm57l8qitqqwyb2r.png)
The graph of the solution set in the attached figure
Explanation:
Let
d ----> the possible number of donuts Monica brought
we know that
The number of donuts d multiplied by $0.50 plus the cost of a box of coffee for $5 must be less than $15
so
The inequality that represent this situation is
![0.50d+5 < 15](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6hmjvyekshbhzebkhvj1655t9ai8ps4u4u.png)
Solve for d
subtract 5 both sides
![0.50d < 15-5](https://img.qammunity.org/2021/formulas/mathematics/middle-school/kfp20gaskxf0rfg4l8nrmqpnkw89c54m4u.png)
Divide by 0.50 both sides
![d < 20\ donuts](https://img.qammunity.org/2021/formulas/mathematics/middle-school/t8h5ysrjo3vmxs4h2fwm57l8qitqqwyb2r.png)
The solution is all whole numbers greater than zero and less than 20 ( I say greater than zero because the problem states that Monica brought some donuts)
The solution set is the interval {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19}