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Monica brought some donuts for $0.50 Each and a box of coffee for $5.

Write and solve an inequality to find the possible number of donuts,d, she brought if she spent less than $15. Then graph the solution set

User Zane XY
by
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1 Answer

3 votes

Answer:


d < 20\ donuts

The graph of the solution set in the attached figure

Explanation:

Let

d ----> the possible number of donuts Monica brought

we know that

The number of donuts d multiplied by $0.50 plus the cost of a box of coffee for $5 must be less than $15

so

The inequality that represent this situation is


0.50d+5 < 15

Solve for d

subtract 5 both sides


0.50d < 15-5


0.50d < 10

Divide by 0.50 both sides


d < 10/0.50


d < 20\ donuts

The solution is all whole numbers greater than zero and less than 20 ( I say greater than zero because the problem states that Monica brought some donuts)

The solution set is the interval {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19}

Monica brought some donuts for $0.50 Each and a box of coffee for $5. Write and solve-example-1
User Afeygin
by
5.6k points
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