For the Data Set below, calculate the Variance to the nearest hundredth decimal place. (Do not use a coma in your answer) 175 349 234 512 638 549 500 611

Question

asked Aug 2, 2021 41.6k views

1 Answer

Wykk · Answer 1 · 2021-08-09T03:09:41+0000

Answer:

The variance of the data is 29966.3.

Explanation:

The given data set is

175, 349, 234, 512, 638, 549, 500, 611

We need to find the variance to the nearest hundredth decimal place.

Mean of the data

$Mean=(\sum x)/(n)$

where, n is number of observation.

Mean=(3568)/(8)=446

The mean of the data is 446.

$Variance=(\sum (x-mean)^2)/(n-1)$

Variance=((175-446)^2+(349-446)^2+(234-446)^2+(512-446)^2+(638-446)^2+(549-446)^2+(500-446)^2+(611-446)^2)/(8-1)

Variance=(209764)/(7)

Variance=29966.2857

$Variance\approx 29966.3$

Therefore, the variance of the data is 29966.3.