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Point C = (4/9,-5/9) lies on the circle with the center at S=(-2/3, 3/4). If CD is a diameter of circle S, find the coordinates for D. Answer must be given as a simplified fraction to receive full credit.

User Joshdholtz
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1 vote

Answer:

Explanation:

If CD is a diameter of circle S, then CD goes through circle S at point S. CS is a radius, and so is DS. That means that they are the same length. That also means that S is the midpoint of CD. We can use the midpoint formula and the 2 points we are given to find the other endpoint, D.


(-(2)/(3),(3)/(4))  =(((4)/(9)+x )/(2),(-(5)/(9)+y )/(2))

To solve for x, we will use the x coordinate of the midpoint; likewise for y. x first:


-(2)/(3)=((4)/(9)+x )/(2)

Multiply both sides by 2 to get rid of the lowermost 2 and get


-(4)/(3)=(4)/(9)+x

Subtract 4/9 from both sides to get


x=-(16)/(9)

Now y:


(3)/(4)=(-(5)/(9)+y )/(2)

Again multiply both sides by that lower 2 to get


(3)/(2)=-(5)/(9)+y

Add 5/9 to both sides to get


y=(37)/(18)

And there you go!


D(-(16)/(9),(37)/(18))

User LynAs
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