Answer:
Explanation:
If CD is a diameter of circle S, then CD goes through circle S at point S. CS is a radius, and so is DS. That means that they are the same length. That also means that S is the midpoint of CD. We can use the midpoint formula and the 2 points we are given to find the other endpoint, D.
![(-(2)/(3),(3)/(4)) =(((4)/(9)+x )/(2),(-(5)/(9)+y )/(2))](https://img.qammunity.org/2021/formulas/mathematics/high-school/k95zvizeaflcmb4qbr94p0j3o1kd9a2vgu.png)
To solve for x, we will use the x coordinate of the midpoint; likewise for y. x first:
![-(2)/(3)=((4)/(9)+x )/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/d3vqureikocz6sxo4bnz5a60csdv83nfut.png)
Multiply both sides by 2 to get rid of the lowermost 2 and get
![-(4)/(3)=(4)/(9)+x](https://img.qammunity.org/2021/formulas/mathematics/high-school/fuqk5ha41qn5p5qo11z4bba9fl6klp4hov.png)
Subtract 4/9 from both sides to get
![x=-(16)/(9)](https://img.qammunity.org/2021/formulas/mathematics/high-school/tcspflfo9ucxcsigf9lekqkc7gr8jggfzi.png)
Now y:
![(3)/(4)=(-(5)/(9)+y )/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/9t3shzhjjq2alxaar2ky22q9h8daaljcuq.png)
Again multiply both sides by that lower 2 to get
![(3)/(2)=-(5)/(9)+y](https://img.qammunity.org/2021/formulas/mathematics/high-school/kxet66typ5ehyp626adlcs6qpmg1hzclnx.png)
Add 5/9 to both sides to get
![y=(37)/(18)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ic11tr38tsgvfeemaxkfzldavsbjwtcbds.png)
And there you go!
![D(-(16)/(9),(37)/(18))](https://img.qammunity.org/2021/formulas/mathematics/high-school/wuz4opczc3uhrmp34sad699l8y96z0rdvs.png)