Question

determine the molarity of a solution made by dissolving 9.51 g of k2so4 in water where the final volume of the solution is 750.0 ml.

Answer 1

We are given –

• Weight of
  `\bf K_2SO_4` is = 9.51 g
• Volume, V = 750 ml

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Molar Mass of
`\bf K_2SO_4` –

`\qquad`
`\twoheadrightarrow\bf 39.09 * 2 + 32 + (16 * 4)`

`\qquad`
`\twoheadrightarrow\bf 174.2`

Using formula –

`\qquad`
`\purple{\twoheadrightarrow\bf Molarity _((Solution)) = ( W* 1000)/(MV)}`

`\qquad`
`\twoheadrightarrow\bf Molarity _((Solution)) = ( 9.51 * 1000)/(174.2* 750)`

`\qquad`
`\twoheadrightarrow\bf Molarity _((Solution)) = (9510)/(174.2 * 750)`

`\qquad`
`\purple{\twoheadrightarrow\bf Molarity _((Solution)) = 0.073M}`

• Henceforth, Molarity of the solution is = 0.073M.

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