26.5k views
4 votes
find the probability of making a five digit number form 2,3,4,7,8 in such a way that 7 is the first number and 8 is the last number

User Lashawnda
by
8.5k points

1 Answer

1 vote

Answer:

n(E) = 6

Explanation:

That's to say that there are 6 five-digit numbers with 7 in the first place and 8 in the last place, using the digits 2, 3, 4, 7 and 8. Therefore n(E) = 6.

User DavidWinterbottom
by
7.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories