Question

find the probability of making a five digit number form 2,3,4,7,8 in such a way that 7 is the first number and 8 is the last number

Answer 1

n(E) = 6

Explanation:

That's to say that there are 6 five-digit numbers with 7 in the first place and 8 in the last place, using the digits 2, 3, 4, 7 and 8. Therefore n(E) = 6.