Question

X, y, z are each a different digit
a. Max(2x+3y+7z)=?

Answer 1

101

Explanation:

To get the largest weighted sum, you want to give the largest weight to the largest possible digit.

Max( ) = 7·9 +3·8 +2·7 = 63 +24 +14 = 101 . . . . (x, y, z) = (7, 8, 9)

The maximum sum is 101.