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X, y, z are each a different digit a. Max(2x+3y+7z)=?
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4 votes
X, y, z are each a different digit
a. Max(2x+3y+7z)=?

User Nahouto
by
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1 Answer

3 votes

Answer:

101

Explanation:

To get the largest weighted sum, you want to give the largest weight to the largest possible digit.

Max( ) = 7·9 +3·8 +2·7 = 63 +24 +14 = 101 . . . . (x, y, z) = (7, 8, 9)

The maximum sum is 101.

User Chee
by
4.8k points
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