Question

4y^3-9y=0 solve by factoring

Answer 1

`y_1=0,y_2=(3)/(2),y_3=(3)/(2)`

Explanation:

`4y^3-9y=0`

`y(4y^2-9)=0`

`y(2y-3)(2y+3)=0` <-- Difference of squares

`y_1=0,y_2=(3)/(2),y_3=(3)/(2)`