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4y^3-9y=0 solve by factoring

1 Answer

3 votes

Answer:


y_1=0,y_2=(3)/(2),y_3=(3)/(2)

Explanation:


4y^3-9y=0


y(4y^2-9)=0


y(2y-3)(2y+3)=0 <-- Difference of squares


y_1=0,y_2=(3)/(2),y_3=(3)/(2)

User Mohammad Fatemi
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