Question

Select the correct answer.
Solve the equation by completing the square.
0=x^2-14x+46

Answer 1

`x=7+√(3),\:x=7-√(3)`

Explanation:

`\mathrm{Switch\:sides}`

`x^2-14x+46=0`

`\mathrm{Solve\;wit\;Quadratic\;formula}`

`x_(1,\:2)=(-\left(-14\right)\pm √(\left(-14\right)^2-4\cdot \:1\cdot \:46))/(2\cdot \:1)`

`√(\left(-14\right)^2-4\cdot \:1\cdot \:46)}{2\cdot \:1}=2√(3)`

`x_(1,\:2)=(-\left(-14\right)\pm \:2√(3))/(2\cdot \:1)`

`\mathrm{Separate\:the\:solutions}`

`x_1=(-\left(-14\right)+2√(3))/(2\cdot \:1),\:x_2=(-\left(-14\right)-2√(3))/(2\cdot \:1)`

`\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}`

`x=7+√(3),\:x=7-√(3)`

~Lenvy~